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Why isn't that code flipping an array?

#include <stdio.h> #include <stdlib.h> int main() { int m [6]={1,2,3,4,5,6}; int i=0; int h; int y; int k =0; int length =sizeof(m)/sizeof(int); for(i=0,y=length;y>0;i++,y--){ //for(y=length;y>0;i--){ //while h=m[i]; m[i]=m[y]; m[y]=h; } printf("\nResult of an Reverse array is: "); for (k = 0; k < length; k++) { printf("%d", m[k]); } }

21st Aug 2018, 2:16 PM
Retag Tarek
Retag Tarek - avatar
1 Answer
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Here is a corrected version of your code: #include <stdio.h> #include <stdlib.h> int main() { int m [6]={1,2,3,4,5,6}; int i=0; int h; int y; int k =0; int length =sizeof(m)/sizeof(int); for(i=0,y=length - 1; y>= length / 2; i++,y--) { h=m[i]; m[i]=m[y]; m[y]=h; } printf("\nResult of an Reverse array is: "); for (k = 0; k < length; k++) { if (k != 0) { printf(", "); } printf("%d", m[k]); } } Here are a few of your mistakes. - In your first loop, y must not start at length. It must be length - 1 since you read its value m[y]. Reading m[length] is 1 element passed the end of the array and risks anything from a memory access violation to merely reading a value you never set. - The first loop loops i from 0 to length when it should loop over only half of it. After looping past the half way mark, you start swapping the same pairs again and restoring their original values. - This is pretty minor but I thought you'd want commas or spaces to separate the numbers when you print them out in the second loop.
3rd Mar 2021, 4:46 PM
Josh Greig
Josh Greig - avatar