hey guys can you help me to understand why 00000100 is 64 ?

Answer 1

guys the position of 1 is the 3rd

Answer 2

at 3rd position is 4bit

Answer 3

always raise in 3

Answer 4

001000000 = 2^6 =64
counting from the right, the first spot has value 2^0, the second 2^1 and so on. The 1 is in place with value 2^6.

Answer 5

so it actually is equal to 4 but we assumed it was read backwards

Answer 6

ill try this in c
ex: int x = 00000100;
printf("%d",x);
result: 64
why??

Answer 7

but if we read backward the result is 32 because the 64 is the second position start from last

Answer 8

128,64,32,16,8,4,2,1 normal
1,2,4,8,16,32,64,128 backwards
my position of my 1's is the 3rd position 😯 in normal and 6th position backwards

Answer 9

oh guys i know now
the formula
my 1's is the position of 3rd and the value is 4 now we need it to raise in 3 to get the value
4*4*4 = 64
and if we try in 01000000
you get the value if you raise the bit in 3 😃

Answer 10

Numbers in C are read in different bases based on the prefix:
No prefix -> decimal (base 10)
'0' prefix -> octal (base 8)
'0x' prefix -> hexadecimal (base 16)
'0b' prefix -> binary (base 2)
When you write 00000100 the compiler sees that it starts with '0' and assumes it to be base 8.
https://code.sololearn.com/cU3TDoNmza71/?ref=app

Answer 11

isn't it in octodecimal, 10 = 8, 100 = 8*8 = 64

Answer 12

64 in binary is:
(64)(32)(16)(8)(4)(2)(1)
1. 0. 0. 0. 0 0. 0
what is 12 in binary?
0001100

Answer 13

00000100 is 4, not 64

Answer 14

Gutch From Ph Yep and you raise in 3 because it's base 8 (2^3). 010000000 would be 128*128*128, or 8^7.

Answer 15

correct, just read it left to right.