Udemy function problem

Question

I have been doing a python course on Udemy to supplement the lessons from Sololearn. The problem below has been the hardest I've come across so far and as a result I was happy to just make it work after playing around with it for several hours. And I neglected to solve the 'empty list' output. My code is much more convoluted than the solution given in the course but I'm intrigued to see how other people would solve this, and how I can clean up the code further.
"""
SUMMER OF '69: Return the sum of the numbers in the array, except ignore sections of numbers starting with a 6 and extending to the next 9 (every 6 will be followed by at least one 9). Return 0 for no numbers.
summer_69([1, 3, 5]) --> 9
summer_69([4, 5, 6, 7, 8, 9]) --> 9
summer_69([2, 1, 6, 9, 11]) --> 14
"""
def summer_69(arr):
for pos, nums in enumerate(arr):
# Separate the nums and index positions from the list
if 6 not in arr:
# if not 6 is in the list, calculate the sum and break
print(sum(arr))
break
elif nums == 6:
six_index = pos
elif nums == 9:
nine_index = pos
idx_lst = arr[six_index: (nine_index +1)]
# Slice the list between the 2 indices
counter = len(arr[six_index: (nine_index +1)])
# Counter based on the number of values between 6 and 9
for x in idx_lst:
arr.remove(x)
counter = counter - 1
if counter == 0:
print(sum(arr))
else:
pass
# I tried moving and removing this but the code wouldn't work otherwise (I dont know why)

Answer 1

Thanks Kishalaya. I think this is exactly the sort of thing I was trying to do but I don't yet have a good enough understanding of the language to be able to do it

Answer 2

Try this:
def so69(a):
while 6 in a:
del a[a.index(6) : a.index(9)+1]
return sum(a)
I'm assuming,
1. There could be multiple 6-9 sections.
2. It's okay to alter the list.

Answer 3

You are welcome, Rob! I can see that you were on the right track.
Let us know if you need more help.
Happy coding :)

Answer 4

# try it.....
def summer_69(arr):
Sum=0
for n in range(0, len(arr)):
if arr[n]<6:
Sum+=arr[n]
elif arr[n]>9:
Sum+=arr[n]
else:
pass
return Sum