What is the reason behind error in this code ?

Question

int a=028;
System.out.println(a);

Answer 1

when you add 0 to the beginning it is considered as octal digit (base 8)
so, it displayed value too large
Ref:
https://stackoverflow.com/questions/6935345/why-is-09-too-large-of-an-integer-number

Answer 2

The presence of 0 as the very first digit of the number 028 makes JVM consider it as an Octal number with base 8. Since octal numbers can never contain a digit greater than 7, it gives an error. 028 is not fundamentally an octal number!

Answer 3

thank you, for posting this question.

Answer 4

it's because 8 doesn't exist in base8

Answer 5

remove the zero

Answer 6

thanks dev and sreejith these explanations are very helpful

Answer 7

System.out.print(a);

Answer 8

whenever you start assigning integer from 0 then JVM assumes that it is as an Octal value. as you here defined here as integer but JVM will interpret as Octal so it will throw error.

Answer 9

You cant have the 0 at the beggining