How to measure the execution time of this code snippet?

def sumOfN(n): return (n*(n+1))/2

6/19/2018 1:20:34 PM

2 Answers

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you can mesure the time execution with using in first line: "start=time.time()" and the final line: "print(time.time()-start)" and it will give you the time ,

Sousou

there's no way to "measure" code execution in milliseconds per se, but if you used big O notation, this code has a time of O(1)

hinanawi