final method in java

Question

I have read that private methods of superclass are considered to be final methods and can't be overriden but I am able to override one.How?
class A
{
private void show()
{
System.out.println("class A");
}
}
class B extends A
{
void show()
{
System.out.println("class B");
}
}
class test
{
public static void main(String[] args)
{
B obj=new B();
obj.show();
}
}
OUTPUT: class B

Answer 1

becoz static
method cant be overriden..
its is called function hiding

Answer 2

harshit
this is not a function overriding.
what you do is just static binding.
as you know
.
you already bind the object with its functionality at compile time..
at function overriding...
binding of object is always at run time.
it means jvm take decision which one it run..
if you change
A obj=new B();
than you see the error
try to run this code
making your function private
and not private
class B extends A
{
public static void main(String[] args)
{
A obj=new B();
obj.show();
}
}
class A
{
void show()
{
System.out.println("class A");
}
}

Answer 3

ok thanks,but I have encountered a new problem.When I have made the method static the output is not "class B" instead it's "class A".Why?
class A
{
static void show()
{
System.out.println("class A");
}
}
class B extends A
{
static void show()
{
System.out.println("class B");
}
}
public class test
{
public static void main(String[] args)
{
A obj=new B();
obj.show();
}
}

Answer 4

thanks