what is the output of def func(x): res = 0 for i in range(x): res += i return res print(func(4))?

Question

the code is from python

Answer 1

10
EDIT: in range function, Loop iterates till limit -1, in this case, it will iterate till 3.
So the answer would be 3+2+1 = 6

Answer 2

The loop runs four times 0-3
res += i
res = res + i
res = 0 + 0 = 0
res = 0 + 1 = 1
res = 1 + 2 = 3
res = 3 + 3 = 6

Answer 3

That's right, Abishek. However knowing how to get 6 is for more important than just the correct answer

Answer 4

answer is 3 not 6

Answer 5

*pass 4 as parameter to function func
*res is set to 0
*a for loop (runs 4 times), i for each number between 0 and 4
*res = res + i
*returns the value of res

Answer 6

6 is the correct answer

Answer 7

In range function, Loop iterates till limit -1, in this case, it will iterate till 3
therefore 1+2+3=6 (6 is the correct answer)

Answer 8

What's the output of this code?
def func(x):
res = 0
for i in range(x):
res += i
return res
print(func(4))
The loop runs four times 0-3
res += i
res = res + i
res = 0 + 0 = 0
res = 0 + 1 = 1
res = 1 + 2 = 3
res = 3 + 3 = 6

Answer 9

alright so I thought I understood the logic here but I am clearly missing something.
def func(x):
res = 0
for i in range(x):
res += i
return res print(func(4))

Answer 10

alright so I thought I understood the logic here but I am clearly missing something.
def func(x):
res = 0
for i in range(x):
res += i
return res print(func(4))

Answer 11

What is the output of this code? def func(x):
res = 0
for i in range(x):
res += i
return res
print(func(4)
Anyone give answer

Answer 12

What is the output of this code?
def func(x):
res = 0
for i in range(x):
res += i
return res
print(func(4))
=6

Answer 13

the output will be 3 as last element 3 is excluded.
es += i
res = res + i
res = 0 + 0 = 0
res = 0 + 1 = 1
res = 1 + 2 = 3

Answer 14

can you explain the meaning and how exactly you got it?

Answer 15

How the answer is 6?

Answer 16

answer is 6

Answer 17

thank you guys ...
I plotted 6 and it was correct