c++ brute-force password cracking algorithm..

Question

I want to make a simple brute-force password app that can crack a password with 5 to 7 length and also works with letters+numbers password..but I completely have no idea what to do with cracking the characters in the password..only know the password with numbers only..This is my unfinished code..
#include <iostream>
using namespace std;
int main()
{
int password;
cout << "Enter a password to bruteforce.. : ";
cin >> password;
for (int i = 0; i < 999999; i++) {
if (i == password) {
cout << "The brute-forced password is = " << i << endl;
break;
}
cout << "Loading..[" << i << "]\n";
}
return 0;
}
but this will only crack a password with length of 6 since i set the condition in for loop 999999.. Need someone to explain and also teach me how to make the code..i don't care if the brute-force takes too long to crack a longer password.. I just want to know how it works.. :) :)

Answer 1

maybe you can use ASCII code. Where each char represent a number. refer to ASCII table, c++ ascii

Answer 2

Passwords are usually strings.
To simply bruteforce the password you should iterate through all the characters. Assuming you have only letters a, b, you want the code to test:
aaa
aab
aba
abb
baa
bab
bba
bbb
When the last position checks the whole range, you increment the last but one, when you check all options for last but one, increment the last but two and so on until all combinations are checked. Then you increment the length and start over.
Since nesting *length* for loops is a bad idea you need another way to iterate. I'd suggest having a string with the current password in memory. After checking you increment the last character and check if it's out of range. If it is not, check the password, if it is, assign it to the first character in range and increment the lust but one and so on. When the first character is out of range, you've checked every combination for the current length.
I'd suggest lengths below 5 characters because of rather high amount of combinations :)

Answer 3

strings should work like arrays, you should be able to access individual characters of string s using s[index] where index is a position. characters are of type char, and what their values correspond to is in the ASCII table as was said before. you can compare them and you can += them. good luck ;)

Answer 4

I just don't know what code that can handle the string passwords..like if it found a same character in a string as the password..it will pop out from the variable and assign the value to the other variable..and then start loop back but without the popped out character..and if found a same character in..and so on
don't know how to make the pop out thing..or there is another ways to code??

Answer 5

Sorry, my previous post might have misled you, but nice idea with listing the available alphabet. Actually "sting alphabets[26]" will produce an array of 26 strings where you need just one :)
Your loop iterates through all of the strings in the "alphabets", once. And the conditional tests if it is the first letter of password. If it is then it concatenates bruted and i-th string in "alphabets" and stores it in "bruted".
I'll sugest just altering characters in "bruted".
I'll give you a piece of code and leave the fun part for you to fill :)
#include <iostream>
#include <string>
using namespace std;
//main
int main() {
//declarations
bool finished = false;
bool found = false;
string alphabets = "abcdefghijklmnopqrstuvwxyz";
string bruted = "zzzz"; //because we want to iterate first in the loop and check password later, so the first checked will be "aaaa"
string password;
//get password from the user
cout << "Enter a 4 letter password: "; cin >> password;
//loop while the password is not found and there are remaining combinations
while (!(finished || found)) {
//TODO: find next "bruted" value to check
//TODO: check if "bruted" is the password and set "found"
//TODO: check if it is a last possible option and set "finished"
}//while
//output findings
if (found) {
cout << "The password is: " << endl;
} else if (finished) {
cout << "No 4 character password found" << endl;
} else {
cout << "This line should never happen" << endl;
}//if
}//main

Answer 6

I just finished writing one for 2-6 characters in length, and it can be adapted to more characters, but I kept it at 6 due to how long it may take to run at anything more than that. You can check it out on my profile.

Answer 7

The two ciphertext’s below were created by either a shift cipher and/or Vigenere cipher. You are to break the
ciphers by recovering the key used on each case.
Ciphertext A
LLGXOGTMWKOBNAEOIZLNGXIGCAUUENWKAXOGSIJDGZTLWCEVEHSCIPVOFRQFMAUUIA
OHWZCGOOOXPVDLGKLJSEJOPREHGEOUEILGIFEHWLMFEMSNMNSOEOQAEHWGQYOEJX
MFDHWLCVWTSMIOTNSXLNHIFDMEDTGBMNYDZOXYZWWNCCEHWQZBFNVLGGSEUYTQW
ACOAUZRWKVQEHWYBUPRLBIIPLWBAPLMWGIYVIFQLBHNLRMGCAUUIAOTZOGAPVWBER
YTXEZGSEJXWGSEQXMIPROOVGMAUUBUPNUKUREHWMPHCCZOAGSEFMIZPTZOAPSOGV
AGSEFMIZPTZOTNHYWBAGSEFMIZPTZOZHWEKDPRYCSWMGSELBIVYSSXLGSELBCPVSOS
BUEHWSZYZAVCIAOTZOLVCTQYTQERSMSJLSLRMGPLWQZNAHJYIQEHWXKNXELRMZTNW
CBUPNUKUREHWYZREHWXBUPRWGIFEHWRIEOTAWMFEHWXBUPRWGIFLWSBBRWEYBIC
SSSXONDOFQIOZULDPRHOJVLBFTKSLREEDOOELPZBWNOGGDABOEWZIAOSGGQQPLAUM
NCODVQARAFMELNVWGELDAYANJSLYVVRHLSBFROFXISCEWJMCPOHVMQCINSVTSOEONE
ZMLRMSLCLYZVPSLRMEPSKSFYLNWCWSERSPNVNTZBMRWAFOAZZVAXOFWOOSCFPDLY
TVVELYOBEOOYZXMULDPRJSZEBVEDGGVVROLKZVRHLDWTZTGGWEVBMDBUPRWCVBHO
JUPRCELYJRQOMXLLPSSXLGSEQCILHEJOOBYNSRIIPTGZILHHSDABHEVGMEPGGXVNSANO
BBCESZNEZMKYURDEWNBULTKLMRYSGGMQLNVDPRMIJNAHAOFDPRHIJOANYDLRMGPL
WQZNAHHYTRDTZOGPLNSVENJSXVGNHAQPZBXTZSAELIFKVQEHACKBWDQYCPLNZOIEEH
WWAVYGAXOBFTLRMVCTWVMTCAHRKBOESVTGSEOKGQZWFDPREEDOOELPZBWNOYGE
SAZWANABZNWBNBCGWDJHEIJOURXBWBBUZSWXQTSTKGPRYLAPMJLSBEAGLBWDWALR
SMMOPTOOMAEHWVQTSTKIWHSAVIWHCHWKLBYMQCPBFLVOZLZUZKLLZUJRIAOIFWGULI
JXWJJOMKKGLLADBYPCGVLRCLAUMLZUVYVGDEWWBBNAJOJHEBWVQRGEAXURMATIIAOI
DVBNVEQYCNHAQPZBXOMDWSEHACLNCKFOAFLNVSVGZTZOLNJFJYUGSEKOZVGEJCWSS
ESNTVRHLCBUPSWBQIPRKYNELIFPZBXTZOIAREJDPNELAFMFZNLRMFERWOBFHILRBUPS
WXIZPSUYAVGEJEVRGEJIZROLAQPGZNEOUBCYDKVRTVWCMRYDWCXRCALSWAPXHVWQP
IFDWSWAEOANYDANWAEWSXBGZSWOQGLGSSVSCOEKTYZFLRMFPSAQVFDAQSVTDOJBG
OFTOOZRNLGCMQLLDDPRHAQNWJYTZOBRWEYBICSRGKL

Answer 8

help me with code to generate passwords with brute force
. Use a Java program to guess the passwords of Moodle users. This is a brute-force attack. Each group
should choose a group leader who in turn will email me to get a list of usernames whose accounts are
to be compromised by guessing the account password. Typically passwords have the following
characteristics:
1. It is either a 6 digit password or
2. 6 lowercase characters or
3. 6 lowercase/uppercase characters or
4. 6 lowercase/uppercase/digit characters or
5. 8 lowercase characters or
6. 8 lowercase/uppercase characters or
7. 8 lowercase/uppercase/digit characters or
8. 9 lowercase characters or
Each group will have exactly 1 user using a password from each group. The users are given in another
document included in the assignment folde

Answer 9

gvgvxsz

Answer 10

help me

Answer 11

Instagram password hack

Answer 12

Gujugril_

Answer 13

Gujugril_ password hack

Answer 14

Is it work ?

Answer 15

Please unlock my Mobile

Answer 16

#include <iostream>
using namespace std;
int main()
{
int password;
cout << "Enter a password to bruteforce.. : ";
cin >> password;
// تصحیح: محدوده بررسی را تا عدد وارد شده توسط کاربر تغییر می‌دهیم
for (int i = 0; i <= password; i++) {
if (i == password) {
cout << "The brute-forced password is = " << i << endl;
break;
}
cout << "Loading..[" << i << "]\n";
}
return 0;
}

Answer 17

"These changes make the loop execute up to the number entered by the user and prevent infinite execution."

Answer 18

It will be too slow unless you have a super computer