Basic operation on cout

Question

for (int m=0;m<3;++m)
{
cout << m%2?m:m+2;
}
why output of this code is 010 ?

Answer 1

The reason why you got 010 instead of 214 is because the statement was evaluated as:
(cout << m%2)?m:m+2;
instead of
cout << (m%2?m:m+2);
http://en.cppreference.com/w/cpp/language/operator_precedence

Answer 2

It seems that c++ just looks at m%2 if you don't put the whole block in parentheses:
cout << (m%2?m:m+2)

Answer 3

Rahul George 214 is correct:
m = 0 -> false -> m+2 = 2
m = 1 -> true -> 1
m = 2 -> 2%2=0 -> false -> m+2 = 4

Answer 4

No paranthesis changes precedence level. Modulus has highest precedence and will do it first.

Answer 5

endoo emo

Answer 6

thanks to all

Answer 7

214

Answer 8

in c++ how can i solve if a problem can make?

Answer 9

то