Loop

Question

In for(i=4; i<8; i++) {
if (i == 6) {
continue;
}
sum += i;
}
does it execute i++ first or the code block first?

Answer 1

Yes. Step by step, your example will do:
i set to 4
i is less than 8 so do the code block, then increment i ( so i is now 5 )
i is less than 8 so do the code block, then increment i ( so i is now 6 )
i is less than 8 so do the code block, then increment i ( so i is now 7 )
i is less than 8 so do the code block, then increment i ( so i is now 8 )
i is not less than 8, so don't do the code block and jump after...
but in the code block there's first a conditional "continue" statement: so when i is equal to 6, the last part of the code block is not executed (sum += i) ;)

Answer 2

The code block first

Answer 3

first i is set to 4 and code block executes then i value increments till the condition i<8
once the condition fails execution of for loop is completed

Answer 4

The for parenthesis parameters is semi-colon separated in three parts: for (<initialisation>; <condition>; <end loop code>)...
<initialisation> is done once, before starting the loop, and never repeated, and usualy is used to initialize a counter.
<condition> is tested at each iteration, before starting code block execution, and exit/jump after the loop code block if false.
<end loop code> is done at each iteration end (after code block execution), and is usualy used to increment or decrement the counter.

Answer 5

Thx

Answer 6

So it will set i to 4, check to see if it's less than 8, do the code block, increment i by 1, and then do the whole thing again except for the part i = 4?