In c the operators *,/,% which has the higher priority?

Question

please tell 2*6/4%2=?

Answer 1

* , / , % have same precedence ... so associativity plays all game in this case ,
associativity is from left to right , which means that if these are present together ... then the operator which comes first from the left will get executed first ... ie first * then / & the % in above case
//hope it helps best to understand precedence & associativity for these operators

Answer 2

for more information as my friends said above check that:
http://en.cppreference.com/w/c/language/operator_precedence

Answer 3

For what I know they have the same precedence.
but in situations like the expression:
2 * 6 / 4 % 2
They are evaluated from left to right.
So a step by step evaluation would do:
step 1. (2 * 6) / 4 % 2 = 12 / 4 % 2
step 2. (12 / 4) % 2 = 3 % 2
step 3. 3 % 2 = 1
EDITED:
and here is the code to prove:
https://code.sololearn.com/cu7Db4WPkzne/?ref=app

Answer 4

en matematicas existe un orden operacional, en el que cuando no estan las parentesis, se sigue ese orden , ese orden es el mismo que sigue el orden aritmetico de los operadores , estudialo para que no sea tan confuso