For loop & Catch handling

Question

int n=6;
for (int i=0;i <3;++i){
try
n/=i;
}
catch(Exception e){
n+=2;
}
}
//Output:4
tried to solve and i know just a little bit how but i need more explanation why from someone who knows it thank-you😊

Answer 1

n=6
loop 1:
n = 6/0 = ~
call cactch block:
n = 6+2= 8
loop 2: n = 8/1 = 8
loop 3: n = 8/2 = 4
end loop
that's why the out put is 4;

Answer 2

in the first loop the try block throws an exception (divide by 0 ) so the catch block gets executed (n becomes 8). and the rest is explained very well by @th3_c0d3r