[Python] Different types comparison

Question

Why do comparisons of different types not produce an error?
f.e.:
if ("12" == 5):
doSomething()
Because of python is typed language I thought that you can't compare two different types. Correct me if I'm wrong.
Thank ya

Answer 1

You can compare them, but they will return False. That's why the following would print "False"
If "12" == 12:
print("True")
else:
print("False")

Answer 2

I'd guess smaller or larger compares difference in numerical size where == and != compares wether or not something are the same thing of not, and that makes the difference

Answer 3

Yes, it doesn't produce an error. But I was wandering why it doesn't produce an error.
f.e. This code produces an error:
if "12" <= 32:
doSomething()
But this code does not produce an error:
if "12" == 32:
doSomething()
So why equivalence supports different types?

Answer 4

As Markus said.. it is a type error if your checking the value of a string.. comparing them is not a problem. is "12==12.. no, they aren't equals. is "12" > than something.. that is an error