def h(n): f = 0 for i in range(1,n+1): if n%i == 0: f = f + 1 return(f == 2)

Question

The function h(n) given above returns True for a positive number n whenever:
 1) n is a multiple of 2
2)  n is a composite number
3)  n is a prime number
4 )  n has an even number of factors

Answer 1

f = 0 # must be definiert fitst
def h(n):
for i in range(0, n):
if n%i == 0:
f += f
return(f)
The function h(n) given above returns the number of even numbers in range n.

Answer 2

2) n is a composite number. For any explanation regarding my answer, please let me know.

Answer 3

KUNAL SHARMA explain your answer!

Answer 4

how to develop the while loop programme

Answer 5

cant understand anything!!!