Int x=035; int y=014; int c =a+b; what is the value of c

/* here are some special notations for specifying the base*/ //might error will come bcz it will convert it to octal from decimal and int datatype will not be able to hold that large number https://code.sololearn.com/cFhPmtl1XAfT/?ref=app one more thing , u by mistakely wrote a,b in place of x,y & Int in place of int */ https://stackoverflow.com/questions/23039871/why-int-j-012-giving-output-10

sorry in place of 038 use 035 mistake in writing

emm, what? its joke ?

no it's not a joke

answer is 41

okey, why x,y initialized from zero (038, 014) why a and b are not declared, and what means " what is the value of c" it's looks likr trolling, if you try compile it you get error...

0 is used before number because of 0 is used to represent the Octal number

Now i know about octal numbers... https://code.sololearn.com/cjIu9Fg5MwKG/?ref=app ps: correct the post, not c= a + b. c=x+y