Help!

Question

Hi, i'm sorry if that's not the right place to answer this kind of question. I have a problem with my program (a simple one but i'm just starting to code) and i don't know how to resolve it. Is there some forum to post it or does anybody help ?
Sorry again for my bad english, that's french stuff ;)
Thanks!

Answer 1

yeah post your code here along with the problem you faced and you'll surely get help
:)

Answer 2

hey
im guessing that Lire is some sort of Scanner object to read user input and
Lire.i is to input numbers and Lire.S is for strings
why didn't you use the standard scanner object or something

add
Scanner in=new Scanner(System.in);
in the beginning and use
in.nestInt() and in.next() instead of Lire and see if it works

anyway what did you try to do in
for(i=0;i<n;i++){
if(lstNb[i]<lstNb[i+1]){
res=lstNb[i];
lstNb[i]=lstNb[i+1];
lstNb[i+1]=res;
}
}

is it used to sort?

Answer 3

I tested your code and there were few bugs
anyway if you tried to get a list, sort it and print it then this is the fixed code(main mathod)
ps-i assumed you tried to bubble sort
pps-sorry if what I typed is not what you intended... I don't know French
:P :)

output->
How many items do you want in list. N=?
5
What is the 1th element ?
5
What is the 2th element ?
7
What is the 3th element ?
1
What is the 4th element ?
4
What is the 5th element ?
3
Sort : yes or no?
yes
Your list:
Case 1 : 1
Case 2 : 3
Case 3 : 4
Case 4 : 5
Case 5 : 7

//-----------------
public static void main (String[] args) throws java.lang.Exception
{
Scanner in =new Scanner(System.in);
int i,n,k,res;
String c;
String o= "yes";
System.out.println("How many items do you want in list. N=?");
n=in.nextInt();
int[] lstNb = new int[n];
for(i=0;i<n; i++){
System.out.println("What is the "+(i+1)+"th element ?");
k=in.nextInt();
lstNb[i]=k;
}
System.out.println("Sort : yes or no?");
c=in.next();
if(o.equals(c)){
for(int j=0;j<n-1;j++){
for(i=0;i<n-1;i++){
if(lstNb[i]>lstNb[i+1]){
res=lstNb[i];
lstNb[i]=lstNb[i+1];
lstNb[i+1]=res;
}

}
}
System.out.println("Your list: ");
for(i=0;i<n;i++){
System.out.println("Case "+(i+1)+" : "+ lstNb[i]);
}
}
else{
System.out.println("Your cases were saved !");
}
}
}

Answer 4

Yeah, thanks, that's what i want ! :)

ps- What's the difference between "a bubble sort" and an other one ?

Answer 5

well there are few sorting mechanisms and bubble sort is one of them
it isnt much efficient
actually I don't know much about sorting algorithms
if you want to know more visit
https://en.m.wikipedia.org/wiki/Sorting_algorithm

Answer 6

for the question about Scanner

yes
you can define it like a variable
Sololearn course contained tutorials about it
check them out

yes
in.nestInt() is for a integer
in.next() is for a whole line

Answer 7

Alright! Thanks a lot for all your answers, and have a good journey! :)

Answer 8

thanks @Sunera

package arraytest;
import java.lang.String;

public class Liste_Amovible{

public static void main (String[] args) {
int i,n,k,res;
String c;
String o= "oui";
System.out.println("Entrez le nombre d'éléments dans la liste. N = ?");
n=Lire.i();
int[] lstNb = new int[n];
for(i=0;i<n; i++){
System.out.println("Quel entier attribuer à la "+(i+1)+" ème case ?");
k=Lire.i();
lstNb[i]=k;
}
System.out.println("Ranger les nombres par ordre croissant : oui ou non ?");
c=Lire.S();
if(o.equals(c)){
for(i=0;i<n;i++){
if(lstNb[i]<lstNb[i+1]){
res=lstNb[i];
lstNb[i]=lstNb[i+1];
lstNb[i+1]=res;
}
}
System.out.println("Voici la nouvelle liste :");
for(i=0;i<n;i++){
System.out.println("Case "+(i+1)+" : "+ lstNb[i]);
}
}
else{
System.out.println("L'ordre des cases est conservé !");
}
}
}

So I don't understand why "if(o.equals(c))" doesn't work (it's where the programm fail). I have NeatBeans as environment.

Answer 9

Exactly, the program creat an array and can sort the cases in ascending order if the user wishs it

Moreover, i'm not sure to inderstand:
Do I add "Scanner in=new Scanner(System.in);" here:

public static void main (String[] args) {
int i,n,k,res;
String c;
String o= "oui";
Scanner in=new Scanner(System.in);
?

and ist "in.nestlnt()" used to read user input (for numbers) and "in.next()" the same thing but for String ?