+ 2

Python

Ребята, помогите решить задачу ☹️ Вообще не понимаю с чего начинать... вот условия задачи: Напишите программу которая проверяет кипит ли вода. Получите температуру в качестве ввода (по шкале Цельсия) и выведите "Boiling" если температура выше или ровна 100. Пример входных данных: 105 Пример выходных данных: Boiling

9th Apr 2021, 5:19 PM
Rostyslav Baryshok
15 Answers
+ 3
This could work: temperature = int(input()) if temperature >= 100: print('Boiling') else: print('Not boiling')
9th Apr 2021, 9:48 PM
Josh Greig
Josh Greig - avatar
+ 2
Temperature = int(input()) If temperature >= 100: Print(“boiling”) Else: Print (“not boiling”)
16th Apr 2022, 7:25 AM
Chris
Chris - avatar
+ 1
temperature = int(input()) If temperature >= 100: Print ("boiling") else: Print("not boiling")
24th Apr 2021, 11:29 AM
Rakesh Lucky
Rakesh Lucky - avatar
+ 1
Rakesh, Print(with capital P) doesn't exist in Python but otherwise your answer is almost an exact copy of mine from a month earlier.
13th Jun 2021, 12:29 PM
Josh Greig
Josh Greig - avatar
+ 1
14th Jun 2021, 11:54 AM
BuzzTowns
BuzzTowns - avatar
+ 1
THE ANSWER FOR YOUR CODE IS :- Temp=(int(input())) if temp >= 100: print(Not Boiling) else: print( Boiling )
24th Apr 2022, 3:59 AM
AARAV PANDEY
AARAV PANDEY - avatar
+ 1
Конечно, вот простая программа на Python для решения вашей задачи: ```python # Получаем температуру в качестве ввода от пользователя temperature = float(input("Введите температуру в градусах Цельсия: ")) # Проверяем условие if temperature >= 100: print("Boiling") else: print("Not Boiling") ``` Эта программа запрашивает у пользователя ввод температуры в градусах Цельсия, затем проверяет, является ли введенная температура выше или равной 100. В зависимости от результата выводится соответствующее сообщение.
8th Jan 2024, 2:29 AM
𝐀𝐲𝐞𝐬𝐡𝐚 𝐍𝐨𝐨𝐫
𝐀𝐲𝐞𝐬𝐡𝐚 𝐍𝐨𝐨𝐫 - avatar
0
Спасибо 👍 помог очень!
10th Apr 2021, 11:39 AM
Rostyslav Baryshok
0
💌 is app solo learn is very essy
17th Jun 2021, 10:52 AM
Yes r arphat
Yes r arphat - avatar
0
u are all benders
19th Nov 2021, 11:14 AM
Kanye Oman West
0
Solution to the problem. def boiling(temp: int) -> str: return "Boiling" if temp >= 100 else "Not boiling" print(boiling(int(input())))
15th Feb 2022, 3:39 PM
Xander Tedder
0
I don't understand ur language
26th May 2022, 3:35 PM
Hrithika Reddy
Hrithika Reddy - avatar
0
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23rd Sep 2023, 2:56 PM
Samuel Gonzáles
Samuel Gonzáles - avatar
0
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27th Sep 2023, 11:28 AM
meena