What is the process ...in this prog..

Question

int num = 5;

while (num > 0) {
num--;
if (num == 3)
continue;

printf("%d\n", num);
}

Answer 1

num iz 5.

Iz num > 0? YESSSS.
Enter loop.

num-- num iz now 4.
Iz num 3? NOOOO.

Print num. Print 4.

Iz num > 0? YESSSS.
num-- num iz now 3.
Iz num 3? YESSSS.

Continue.

Iz num > 0? YESSSS.
num-- num iz now 2.
Iz num 2? NOOOO.

Print num. Print 2.

Iz num > 0? YESSSS.
num-- num iz now 1.
Iz num 3? NOOOO.

Print num. Print 1.

Iz num > 0? YESSSS.
num-- num iz now 0.
Iz num 3? NOOOO.

Print num. Print 0.

Iz num > 0? NOOOO.
Exit loop.

YAAYY

Answer 2

YAAAAAAY

Sorry, had to do that.

Answer 3

num-- returns the value of num and then increments num. Since you are not assigning num to anything, there is nothing else on the same line as num--. Nothing happens except for the decrement.

Answer 4

oh in this program
u will never get output avoid silly mistakes

Answer 5

yash can u pls explain the errors in my code name
use.

Answer 6

what's ur doubt...

Answer 7

that's according to your code....if i can..then i will...

Answer 8

sowmiya hi

Answer 9

hello...palak...

Answer 10

hlo sowmiya

Answer 11

nega coding error clear panuviya

Answer 12

num=5 ,then
num-- =5 only na...
how it become 4..
this is what my doubt is..
what is the difference between...
--num &num--??

Answer 13

ok frnzz.. sorry i undetstood...
tanq...

Answer 14

ya.. now cleared...